怎么把文件名中的空格全去掉

[DerekTan]

这个问题还有点小难的，我想不到好一点的方法

从光盘上拷来一个文件夹，文件夹包含子目录，子目录里面又有文件，反正还挺多的，好几层~~
这里面的目录名和文件名，有不少包含空格

我想要把目录名、文件名中的空格全部去掉，各位有什么好办法不？

我一开始的想法是find . -name "*", 然后把找到的文件列表传给mv。 实际这样做不行，因为会出现把目录名改了以后，原来find出来的文件路径已经改掉了，mv就不成功了……（囧，我讲清楚没有？）

先谢谢啦:)

[p0p0007123]

不晓得，帮你顶一下。

[yaoms]

代码： 全选

for filename in `find . -name "*"`
do newname="${filename// /}"
newdirname=`dirname $newname`
mkdir -p /newdir/"$newdirname"
cp -v "$filename" /newdir/"$newname"
done

[DerekTan]

代码： 全选

for filename in `find . -name "*"`
do newname="${filename// /}"
newdirname=`dirname $newname`
mkdir -p /newdir/"$newdirname"
cp -v "$filename" /newdir/"$newname"
done

谢谢yaoms，不过可能有点问题，在for filename in `find . -name "*"`这里，find出来的文件名里面已经包含空格了，比如“a b"，$filename会得到两次值，一个是a，一个是b...

[darkfish]

试试

代码： 全选

 rename 's/([^\ ]*) +(.*)/$1$2/' *

[darkfish]

哦，也有问题，只能是一串空格隔开的文件名。（如果反复用N次的话，应该可以解决，嘿嘿）

[xunknown]

用下面在脚本，经过测试：

#!/bin/sh
#使用bash做为默认shell

#create by Alpha @2010-01-08
#本程序的功能是遍历指定目录及其所有子目录，将所有文件名（目录除外）中的空格替换为下划线，

#convert whitesapce to '_' in filename
rename()
{
for file in "$1"/*
do
if [ -d "$file" ]; then
rename "$file" #递归调用，遍历所有子目录
elif [ -f "$file" ]; then
dir=`dirname "$file"`
filename=`basename "$file"`
#echo "dir is ""$dir"
#echo "$filename"

oldname=$filename
newname=
#
for sub in $filename
do
if [ $newname ]; then
newname=$newname"_"$sub
else
newname=$sub
fi
done

if [ "$newname" != "$oldname" ]; then #filename changed
if [ ! -f "$dir/$newname" ]; then #new file not exist
echo "rename file '$dir/$oldname' to '$dir/$newname'"
mv "$dir/$oldname" "$dir/$newname" #rename file
else #new file exist
echo "file exist: can not rename file '$dir/$oldname' to '$dir/$newname'"
fi
else
echo "file '$dir/$oldname' do not need rename."
fi
fi
done
}

#main begin
if [ $# -gt 0 ]; then
echo "All files which filename have whitesapce in folder '$1' and its subfolder will be rename."
else
echo "All files which filename have whitesapce in folder '.' and its subfolder will be rename."
fi

echo "Continue [y/n]?: \c"

read confirm
while [ "$confirm" != "y" ]
do
if [ "$confirm" = "n" ]; then
exit 0
fi

echo "Continue [y/n]?: \c"
read confirm
done

#do rename
if [ $# -gt 0 ]; then
rename "$1"
else
rename "."
fi

[xunknown]

没注意到要改目录名，加上改目录名的功能，用下面代码：

#!/bin/sh
#使用bash做为默认shell

#create by Alpha @2010-01-08
#本程序的功能是遍历指定目录及其所有子目录，将所有子目录、文件名中的空格替换为下划线

#convert whitesapce to '_' in file name
rename_file()
{
for file in "$1"/*
do
if [ -d "$file" ]; then
rename_file "$file" #递归调用，遍历所有子目录
elif [ -f "$file" ]; then
dir=`dirname "$file"`
filename=`basename "$file"`
#echo "dir is ""$dir"
#echo "$filename"

#new file name
oldname=$filename
newname=
for sub in $filename
do
if [ $newname ]; then
newname=$newname"_"$sub
else
newname=$sub
fi
done

#rename file
if [ "$newname" != "$oldname" ]; then #file name changed
if [ ! -f "$dir/$newname" ]; then #file not exist, do rename
echo "rename file '$dir/$oldname' to '$dir/$newname'"
mv "$dir/$oldname" "$dir/$newname" #rename file
else #file exist
echo "file exist: can not rename file '$dir/$oldname' to '$dir/$newname'"
fi
else
echo "file '$dir/$oldname' do not need rename."
fi
fi
done
}

#convert whitesapce to '_' in dir name
rename_dir()
{
for file in "$1"/*
do
if [ ! -d "$file" ]; then
continue
fi

#new dir name
olddir=$file
newdir=
for sub in $file
do
if [ $newdir ]; then
newdir=$newdir"_"$sub
else
newdir=$sub
fi
done

#rename dir
if [ "$newdir" != "$olddir" ]; then #dir name changed
if [ ! -d "$newdir" -a ! -f "$newdir" ]; then #file not exist, do rename
echo "rename dir '$olddir' to '$newdir'"
mv "$olddir" "$newdir" #rename dir
else #file exist
echo "file exist: can not rename dir '$oledir' to '$newdir'"
newdir=$olddir #change var newdir for recurring
fi
else
echo "dir '$olddir' do not need rename."
newdir=$olddir #change var newdir for recurring
fi
rename_dir "$newdir" #递归
done
}

#main begin
if [ $# -gt 0 ]; then
echo "All files which filename have whitesapce in folder '$1' will be rename."
else
echo "All files which filename have whitesapce in folder '.' will be rename."
fi

echo "Continue [y/n]?: \c"

read confirm
while [ "$confirm" != "y" ]
do
if [ "$confirm" = "n" ]; then
exit 0
fi

echo "Continue [y/n]?: \c"
read confirm
done

#do rename
if [ $# -gt 0 ]; then
rename_file "$1"
rename_dir "$1"
else
rename_file "."
rename_dir "."
fi

<<<<<<<<----------以上是最新的－－－－－－－－－－－－－

用下面在脚本，经过测试：

#!/bin/sh
#使用bash做为默认shell

#create by Alpha @2010-01-08
#本程序的功能是遍历指定目录及其所有子目录，将所有文件名（目录除外）中的空格替换为下划线，

#convert whitesapce to '_' in filename
rename()
{
for file in "$1"/*
do
if [ -d "$file" ]; then
rename "$file" #递归调用，遍历所有子目录
elif [ -f "$file" ]; then
dir=`dirname "$file"`
filename=`basename "$file"`
#echo "dir is ""$dir"
#echo "$filename"

oldname=$filename
newname=
#
for sub in $filename
do
if [ $newname ]; then
newname=$newname"_"$sub
else
newname=$sub
fi
done

if [ "$newname" != "$oldname" ]; then #filename changed
if [ ! -f "$dir/$newname" ]; then #new file not exist
echo "rename file '$dir/$oldname' to '$dir/$newname'"
mv "$dir/$oldname" "$dir/$newname" #rename file
else #new file exist
echo "file exist: can not rename file '$dir/$oldname' to '$dir/$newname'"
fi
else
echo "file '$dir/$oldname' do not need rename."
fi
fi
done
}

#main begin
if [ $# -gt 0 ]; then
echo "All files which filename have whitesapce in folder '$1' and its subfolder will be rename."
else
echo "All files which filename have whitesapce in folder '.' and its subfolder will be rename."
fi

echo "Continue [y/n]?: \c"

read confirm
while [ "$confirm" != "y" ]
do
if [ "$confirm" = "n" ]; then
exit 0
fi

echo "Continue [y/n]?: \c"
read confirm
done

#do rename
if [ $# -gt 0 ]; then
rename "$1"
else
rename "."
fi

[eexpress]

？？？？？？？？？这么复杂？？
rename 's/\ //g' * 不行吗？

[DerekTan]

？？？？？？？？？这么复杂？？
rename 's/\ //g' * 不行吗？

光靠这行貌似不行~

[eexpress]

说下。为什么不行。
find可带-exec bash -c '' \;
那''里面可以调用rename xxxx {}的。
怎么样，都是一行代码

[DerekTan]

谢谢xunknown的帮助

试了一下你的脚本，好像子目录的名字没有全部改过来，你看看是不是哪里漏了？仍然很感谢你，你的脚本也给我带来了启发

自己写了一个，

代码： 全选

#!/bin/bash

modifyname()
{
    if [ -d "$1" ]  #directory
    then
        for files in "$1"/*
        do
            modifyname "$files"
        done
    fi
    bname=`basename "$1"` 
        echo $bname | grep -q " " #chech if contains blank
        if [ $? -eq 0 ]
    then
        dname=`dirname "$1"`
        newname=$dname/${bname// /_}
        mv -v "$1" "$newname"
    fi
}

[ -e "$1" ] || { echo "$1 does not exist"; exit 1; }

modifyname "$1"
exit 0

[DerekTan]

说下。为什么不行。
find可带-exec bash -c '' \;
那''里面可以调用rename xxxx {}的。
怎么样，都是一行代码

谢谢小e~~
比如原本有a a/b b b/c c c c
find出来的效果是这样的
./a a
./a a/b b b
./a a/b b b/c c c c
这样先把a a的名字给改了以后，./a a/b b b就不存在了吧？所以rename的时候会出错？

然后我就改成了这样：
find . -name "*" | tac | xargs -I{} rename ' ' '_' {}
还是不行——我测试的时候建了几重文件夹，胡乱放了几个文件，反正有一些没有改过来

另外，那个 rename 's/\ //g' {} 我不太懂……rename不是要三个参数的吗？这里面……

谢谢ee:)

[openware]

恩，ee这招比较帅，抵得上万行代码。

[DerekTan]

恩，ee这招比较帅，抵得上万行代码。

囧。。。我用ee的方法不行啊，是我没有领会到吗？你帮我讲讲撒~~多谢啦！