发现bash -e参数的一个问题
发表于 : 2020-08-11 13:40
按照道理,加上-e参数,当脚本运行中遇到错误时,会立马退出,但我发现当使用&&时会继续执行。如下所示:

为什么第一行命令的返回值非0,bash还继续往下执行了?

为什么第一行命令的返回值非0,bash还继续往下执行了?
-e Exit immediately if a pipeline (which may consist of a single simple command), a list, or a
compound command (see SHELL GRAMMAR above), exits with a non-zero status. The shell does not
exit if the command that fails is part of the command list immediately following a while or un‐
til keyword, part of the test following the if or elif reserved words, part of any command exe‐
cuted in a && or || list except the command following the final && or ||, any command in a
pipeline but the last, or if the command's return value is being inverted with !. If a com‐
pound command other than a subshell returns a non-zero status because a command failed while -e
was being ignored, the shell does not exit. A trap on ERR, if set, is executed before the
shell exits. This option applies to the shell environment and each subshell environment sepa‐
rately (see COMMAND EXECUTION ENVIRONMENT above), and may cause subshells to exit before exe‐
cuting all the commands in the subshell.
注意红字部分。只有是最后一个&&或||之后的命令出错才会退出The shell does not exit if the command that fails is part of any command executed in a && or || list except the command following the final && or ||