Shell小程序，求排错

[潇潇暮雨sunny]

#!/bin/bash

declare counter1
declare counter2
let $counter1 = 1
while [ "$counter1" -lt 6 ]
do echo "Warning: There is a bug in your programme."
let $counter2 = 1
while [ "$counter2" -lt 200 ]
do let $counter2 ="counter2 + 1"
done
clear
let $counter2 = 1
while [ "$counter2" -lt 200 ]
do let $counter2 = "$counter2 + 1"
done
let $counter1 = "$counter1 + 1"
done

./testwhile: 行 5: let: =: 语法错误: 期待操作数 （错误符号是 "="）
./testwhile: 第 6 行: [: : 期待整数表达式

[naturalaw]

赋值时，请不要在等号两边加空格。谢谢
感觉好多错哦。
逻辑很乱。不知道你要做什么。
[bash]#!/bin/bash

#declare counter1
#declare counter2 # 变量直接用，无需声明
#let $counter1 = 1 赋值时，请不要在等号两边加空格。谢谢
#while [ "$counter1" -lt 6 ] 引号内的类型是字符（串）
# do echo "Warning: There is a bug in your programme."
# let $counter2 = 1
# while [ "$counter2" -lt 200 ]
# do let $counter2 ="counter2 + 1"
# done
# clear
# let $counter2 = 1
# while [ "$counter2" -lt 200 ]
# do let $counter2 = "$counter2 + 1"
# done
# let $counter1 = "$counter1 + 1"
#done
##太多错了。我重写一个得了。


counter1=1
while [ $counter1 -lt 6 ];do
echo "Warning: There is a bug in your programme."
counter2=1
while [ $counter2 -lt 200 ];do
counter2=`expr $counter2 + 1`
done
clear
counter2=1
while [ $counter2 -lt 200 ];do
counter2=`expr $counter2 + 1`
done
counter2=`expr $counter1 + 1`
done
[/bash]

[eexpress]

declare，哪里抄来的哦。多过时的用法。

counter1=1 不就完了嘛。

[潇潇暮雨sunny]

感谢指点，但是还是不对，错误如下：./testwhile: 行 5: let: =1: 语法错误: 期待操作数 （错误符号是 "=1"）

[潇潇暮雨sunny]

2001年电子工业出版社出版的书，虽然很过时，觉着读读还是很有用。谢谢各位

[naturalaw]

看2楼，我编辑过了。。不知道你要做什么。

[枫叶饭团]

这破shell有什么用

[naturalaw]

这破shell有什么用

据说运维用得多。